(2c+8)(2c^2-4c-1)=

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Solution for (2c+8)(2c^2-4c-1)= equation:


Simplifying
(2c + 8)(2c2 + -4c + -1) = 0

Reorder the terms:
(8 + 2c)(2c2 + -4c + -1) = 0

Reorder the terms:
(8 + 2c)(-1 + -4c + 2c2) = 0

Multiply (8 + 2c) * (-1 + -4c + 2c2)
(8(-1 + -4c + 2c2) + 2c * (-1 + -4c + 2c2)) = 0
((-1 * 8 + -4c * 8 + 2c2 * 8) + 2c * (-1 + -4c + 2c2)) = 0
((-8 + -32c + 16c2) + 2c * (-1 + -4c + 2c2)) = 0
(-8 + -32c + 16c2 + (-1 * 2c + -4c * 2c + 2c2 * 2c)) = 0
(-8 + -32c + 16c2 + (-2c + -8c2 + 4c3)) = 0

Reorder the terms:
(-8 + -32c + -2c + 16c2 + -8c2 + 4c3) = 0

Combine like terms: -32c + -2c = -34c
(-8 + -34c + 16c2 + -8c2 + 4c3) = 0

Combine like terms: 16c2 + -8c2 = 8c2
(-8 + -34c + 8c2 + 4c3) = 0

Solving
-8 + -34c + 8c2 + 4c3 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-4 + -17c + 4c2 + 2c3) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-4 + -17c + 4c2 + 2c3)' equal to zero and attempt to solve: Simplifying -4 + -17c + 4c2 + 2c3 = 0 Solving -4 + -17c + 4c2 + 2c3 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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